## Discussion Forum

Que. | The following Context-Free Grammar (CFG) : S → aB | bA A → a | as | bAA B → b | bs | aBB will generate |

a. | odd numbers of a's and odd numbers of b's |

b. | even numbers of a's and even numbers of b's |

c. | equal numbers of a's and b's |

d. | different numbers of a's and b's |

Answer:equal numbers of a's and b's |