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Que. The minimum number of states of the non-deterministic finite automation which accepts the language
{a b a bn| n  ≥  0} ∪ {a b an|n  ≥ 0} is 
a. 3
b. 4
c. 5
d. 6
Answer:5

Similar Questions:

The regular grammar for the language L = {a^nb^m | n + m is even} is given by

(A) S → S1 | S2
S1 → a S1 | A1
A1 → b A1 | λ
S2 → aaS2 | A2
A2 → b A2 | λ
(B) S → S1 | S2
S1 → a S1 | a A1
S2 → aa S2 | A2
A1 → bA1 | λ
A2 → bA2 | λ
(C) S → S1 | S2
S1 → aaa S1 | aA1
S2 → aaS2 | A2
A1 → bA1 | λ
A2 → bA2 | λ
(D) S → S1 | S2
S1 → aa S1 | A1
S2 → aaS2 | aA2
A1 → bbA1 | λ
A2 → bbA2 | b
A grammar G is LL(1) if and only if the following conditions hold for two distinct productions A → α | β

I. First (α) ∩ First (β) ≠ {a} where a is some terminal symbol of the grammar.
II. First (α) ∩ First (β) ≠ λ
III. First (α) ∩ Follow(A) = φ if λ є First (β)
We can show that the clique problem is NP-hard by proving that
Given the following two languages:

L1 = {a^nb^n|n≥0, n≠100}
L2 = {w ϵ {a,b,c}*| na(w) = nb(w) = nc(w)}

Which of the following options is correct?
Which one of the following statement is false?
Which one of the following is not a Greibach Normal form grammar?

(i)            S ->a|bA|aA|bB
A->a
B->b
(ii)           S->a|aA|AB
A->a
B->b
(iii)          S->a|A|aA
A->a
Let C be a binary linear code with minimum distance 2t + 1 then it can correct upto ............bits of error.
Assume, L is regular language. Let statements S1 and S2 be defined as :

S1 : SQRT(L) = { x| for some y with |y| = |x|^2, xy ∈L}
S2 : LOG(L) = { x| for some y with |y| = 2^|x|, xy ∈ L}

Which of the following is true ?
Given the following two languages :

L1 = {anbn |n≥1} ∪ {a}

L2= {w C wR|we {a,b}*}

Which statement is correct ?
Which of the following grammar is LR (1)?

View All Questions on: Theory of Computation(TOC)

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