Discussion Forum
Que.  In propositional logic P ⇔ Q is equivalent to (Where ~ denotes NOT): 
a.  ~ (P ˅ Q) ˄ ~ (Q ˅ P) 
b.  (~ P ˅ Q) ˄ (~ Q ˅ P) 
c.  (P ˅ Q) ˄ (Q ˅ P) 
d.  ~ (P ˅ Q) → ~ (Q ˅ P) 
Answer:(~ P ˅ Q) ˄ (~ Q ˅ P)

Que.  In propositional logic P ⇔ Q is equivalent to (Where ~ denotes NOT): 
a.  ~ (P ˅ Q) ˄ ~ (Q ˅ P) 
b.  (~ P ˅ Q) ˄ (~ Q ˅ P) 
c.  (P ˅ Q) ˄ (Q ˅ P) 
d.  ~ (P ˅ Q) → ~ (Q ˅ P) 
Answer:(~ P ˅ Q) ˄ (~ Q ˅ P)

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