## Discussion Forum

Que. | Consider the binary relation: S = {(x, y) | y = x+1 and x, y ∈ {0, 1, 2, ...}} The reflexive transitive closure of S is |

a. | {(x, y) | y > x and x, y ∈ {0, 1, 2, ... }} |

b. | {(x, y) | y ≥ x and x, y ∈ {0, 1, 2, ... }} |

c. | {(x, y) | y < x and x, y ∈ {0, 1, 2, ... }} |

d. | {(x, y) | y ≤ x and x, y ∈ {0, 1, 2, ... }} |

Answer:{(x, y) | y ≥ x and x, y ∈ {0, 1, 2, ... }} |