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Discussion Forum

Que. Consider the binary relation:

S = {(x, y) | y = x+1 and x, y ∈ {0, 1, 2, ...}}

The reflexive transitive closure of S is
a. {(x, y) | y > x and x, y ∈ {0, 1, 2, ... }}
b. {(x, y) | y ≥ x and x, y ∈ {0, 1, 2, ... }}
c. {(x, y) | y < x and x, y ∈ {0, 1, 2, ... }}
d. {(x, y) | y ≤ x and x, y ∈ {0, 1, 2, ... }}
Answer:{(x, y) | y ≥ x and x, y ∈ {0, 1, 2, ... }}
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