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Que. Match all items in Group 1 with correct options from those given in Group 2.

Group 1 Group 2

P. Regular expression 1. Syntax analysis
Q. Pushdown automata 2. Code generation
R. Dataflow analysis 3. Lexical analysis
S. Register allocation 4. Code optimization
a. P-4. Q-1, R-2, S-3
b. P-3, Q-1, R-4, S-2
c. P-3, Q-4, R-1, S-2
d. P-2, Q-1, R-4, S-3
Answer:P-3, Q-1, R-4, S-2
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Similar Questions:

Consider the grammar with non-terminals N = {S,C,S1 },terminals T={a,b,i,t,e}, with S as the start symbol, and the following set of rules:

S --> iCtSS1|a
S1 --> eS|ϵ
C --> b

The grammar is NOT LL(1) because:
The output of a lexical analyzer is
Consider the following code segment.

x = u - t;
y = x * v;
x = y + w;
y = t - z;
y = x * y;

The minimum number of total variables required to convert the above code segment to static single assignment form is
Match all items in Group 1 with correct options from those given in Group 2.

Group 1 Group 2

P. Regular expression 1. Syntax analysis
Q. Pushdown automata 2. Code generation
R. Dataflow analysis 3. Lexical analysis
S. Register allocation 4. Code optimization
Consider the following statements:

(I) The output of a lexical analyzer is groups of characters.
(II) Total number of tokens in printf("i=%d, &i=%x", i, &i); are 11.
(III) Symbol table can be implementation by using array and hash table but not tree.

Which of the following statement(s) is/are correct?
The grammar S → aSa | bS | c is
Among simple LR (SLR), canonical LR, and look-ahead LR (LALR), which of the following pairs identify the method that is very easy to implement and the method that is the most powerful, in that order?
Consider the following grammar:

S → FR
R → S | ε
F → id

In the predictive parser table, M, of the grammar the entries M[S, id] and M[R, $] respectively
Some code optimizations are carried out on the intermediate code because
In the context of abstract-syntax-tree (AST) and control-flow-graph (CFG), which one of the following is True?
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